Skip Navigation

Mathematical Association of America -- American Mathematics Competitions

APMO

2005 Asian Pacific Mathematics Olympiad

XVII Asian Pacific Mathematics Olympiad - 2005

Unofficial Summary of Results

Sponsored by the Canadian Mathematical Society http://www.cms.math.ca/Competitions/APMO/
RANK STUDENT NAME
SCHOOL
TOTAL
1 Yi Sun
The Harker School, CA
Gold
2 Ameya Velingker
Parkland High School, PA
Silver
3 John Kim
Montgomery Blair High School, MD
Silver
4 Brian Lawrence
Montgomery Blair High School, MD
Bronze
5 Tae Hyeon Ko
Phillips Exeter Academy, NH
Bronze
6 Eric Price
Thomas Jefferson High School of Sci & Tech, VA
Bronze
7 Thomas Midorf
Thomas Jefferson High School of Sci & Tech, VA
Bronze
8 Tedrick Leung
North Hollywood High School, CA
Honorable
Mention
9
Adam Hesterberg
Garfield High School, WA
Honorable
Mention
10 Joshua Horowitz
Simsbury High School, CT
Honorable
Mention
2005 Participants
# writing
Mean Pr 1
Mean Pr 2
Mean Pr 3
Mean Pr 4
Mean Pr 5
Mean Total
Gold Awards
Silver Awards
Bronze Awards
Honorable Mention
Argentina
10
7.0
0.7
0.3
10.
103
10.3
1
1
2
5
Australia
10
7.0
0.0
1.7
1.5
0.6
10.8
1
2
4
3
Canada
10
6.6
0.2
5.6
1.6
1.3
15.3
1
2
4
3
Colombia
9
4.2
0.0
0.8
1.1
0.8
6.9
0
2
0
1
Ecuador
6
1.2
0.0
0.0
0.0
0.0
1.2
0
0
0
1
Hong Kong
10
7.0
1.4
3.5
1.1
3.6
16.6
1
2
4
3
Indonesia
4
3.5
1.0
0.8
0.8
3.5
9.5
0
1
0
2
Japan
10
7.0
0.7
2.2
2.1
4.4
16.4
1
2
4
3
Kazakhstan
10
6.3
1.4
1.0
0.4
4.5
13.6
1
2
4
3
Korea
10
6.6
2.0
3.3
1.3
3.4
19.5
1
2
4
3
Mexico
10
5.6
0.0
2.1
0.3
0.4
8.4
0
1
1
8
New Zealand
10
3.0
0.0
0.2
1.2
1.1
5.5
0
1
1
2
Panama
6
0.0
0.7
0.3
0.5
0.0
1.5
0
0
0
0
Peru
10
2.5
0.8
1.9
0.6
2.1
7.9
1
0
1
2
Singapore
10
7.0
0.7
0.7
0.9
0.7
10.0
1
0
3
6
Taiwan
10
6.2
1.4
6.1
1.6
4.9
20.2
1
2
4
3
Thailand
10
6.9
5.6
0.7
0.6
3.6
17.4
1
2
4
3
Trinadad & Tobago
10
0.4
0.1
0.0
0.4
0.0
0.9
0
0
0
0
USA
10
7.0
1.4
2.8
0.8
4.3
16.3
1
2
4
3
# students
175
12
24
44
55
Awards Cut-offs
Overall mean
5.3
1.0
1.9
1.0
2.4
11.5
17.3
13.4
9.5
Overall Standard Deviation
2.3
1.3
1.8
0.5
2.0
5.8
Gold = mean + std.Dev
Silver = mean + 1/3 std.Dev
Bronze = mean - 1/3 std.Dev